x^2+2x+38=0

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Solution for x^2+2x+38=0 equation:


Simplifying
x2 + 2x + 38 = 0

Reorder the terms:
38 + 2x + x2 = 0

Solving
38 + 2x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-38' to each side of the equation.
38 + 2x + -38 + x2 = 0 + -38

Reorder the terms:
38 + -38 + 2x + x2 = 0 + -38

Combine like terms: 38 + -38 = 0
0 + 2x + x2 = 0 + -38
2x + x2 = 0 + -38

Combine like terms: 0 + -38 = -38
2x + x2 = -38

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = -38 + 1

Reorder the terms:
1 + 2x + x2 = -38 + 1

Combine like terms: -38 + 1 = -37
1 + 2x + x2 = -37

Factor a perfect square on the left side:
(x + 1)(x + 1) = -37

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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